Question

RUESLIon (points) For manganese(II) hydroxide, Mn(OH)2, Ksp = 1.6 x 10-13. Calculate the molar solubility of Mn(OH)2 in a solution that contains 0.158 M NaOH. (Hint: this involves calculating the effect of a common ion on solubility.)

Answer 1

271,0 992 manganese (0) Myclooxide _Mncong Mncon), will diſsociate ast con s6 Mn cor e mrt2 + 20h -as 25 Here s is molar Salability of MiCon In presence of Naor;-). As NaOH is strong electrolyte; it will Completely dissociate as it -NaOH Nat + OH (ae) Intial 0.15814 !!! - final 0.158 - 0.158 رضوح Hence in presence of NaOH we can write Mncon ² mit lang + 2OH (99) 28 +04158 from Noor Soy -The Expression for Ksp Ksp - [meta] [or]

CEשע #kep = [5] [R$+-0.1587 30 As S <<< 0.158 so we can ( neglect it Ksp = [s] [ 0.1583& 7.6x1őt? = [3] [0.158] | [3) = 106x1013 6158* 0.158 als 6.42 xlo!2.m Thus, - molar solubility of Mn (on)2 ni in presence of 0.158 m Na OH is 6.41 X1012 m