Answer:
a). B.

t stat = 1.92
P value =0.059
A). Do not reject Ho. There is insufficient evidence that the means differ.
B). In addition to equal variances, no other assumptions must be made because the sample size are large enough( ≥30 for each sample).
|
Pooled-Variance t Test for the Difference Between Two Means |
|
|
(assumes equal population variances) |
|
|
Data |
|
|
Hypothesized Difference |
0 |
|
Level of Significance |
0.05 |
|
Population 1 Sample male |
|
|
Sample Size |
30 |
|
Sample Mean |
159 |
|
Sample Standard Deviation |
203.5182 |
|
Population 2 Sample female |
|
|
Sample Size |
30 |
|
Sample Mean |
84.5 |
|
Sample Standard Deviation |
59.4856 |
|
Intermediate Calculations |
|
|
Population 1 Sample Degrees of Freedom |
29 |
|
Population 2 Sample Degrees of Freedom |
29 |
|
Total Degrees of Freedom |
58 |
|
Pooled Variance |
22479.0948 |
|
Standard Error |
38.7118 |
|
Difference in Sample Means |
74.5000 |
|
t Test Statistic |
1.9245 |
|
Two-Tail Test |
|
|
Lower Critical Value |
-2.0017 |
|
Upper Critical Value |
2.0017 |
|
p-Value |
0.0592 |
|
Do not reject the null hypothesis |
|
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Question 21
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