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1. An object is orbiting around the planet Quakers with an average distance of 75,000 km. The value of k - 6.9 x 10 (units
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Answer #1

1)Cuvendita, K = 619x109 Distance, a = 75000 km From Kepierś zod law, T2 = KA² =(619x109) (75000) 3 (619x109) (4:218 x 104) T2

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