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-6 at 30 ft = 180 ft- 25 k 25k 25L I 20 ft 15 ft 5 ft 45k (g) members CD, DI & DJ (method of sections)
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Free-body diagram: 25k 25k 25K - H. - -.-. - - 45k 6x3oft = 180 ft - - Z - direction ex-direction, E Fe=0 i. Ax=0Taking Moment of all the forces about point A EMASO → 25 X30 +25x60 +25x90 + 45X120 +45 X150 - Gyx 180 = 0 → Gy = 92.5%. {fy=255 25k Ax=0 A soft B soft tc FEDT coft 20. *FIJ Talking Moment of all the forces about point I Ay x 60 – 25x30 – Fest (20 +1JOB 154 FIT FI I on solving equation and ® , we get FID = -45.669 k ccompressive) Fou = -74.164 k ccompressive) Now, for equi

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