Question

Example A strut and cable assembly ABC supports a vertical load P= 1.8 KN. The cable has an effective cross-sectional area of 12000 sq. mm and the strut has an area of 25000 sq.mm. Calculate the normal stress in the cable and strut, and indicate whether they are in tension or compression. Units: m 1.5

Answer 1

Paino HERE Tomo = (ie tamo-P) ou tants 05 5312 Novo Resolve P one elong stoet and once along cable Now For cable 34 in tension because THE FORCE is OUTWARD Now STRESS - CScanned with CamScanner : Pserie

Now Psemo s 1.8 X10% Sem 5310 Pseino = 1:43 x103 AREA OF CABLE : 12000 sq.mm : 12000x10^6 sq metre (1 sqmom s pot : 0.012 S9 metre 30 STRESS IN CABLE : 1.43 X10 0.012 = 119.16 X10 N/m Now You CASE OF STRUT Tha FORCE IS SNWARD 50 Compression NO STRESS : 1:8 X10%cos 53:12 0·025 1:08x109 0.025 = 43.2 x103 Nm Solved Sonne with conscanner Scanned with CamScanner
here in the given question we have to find stress on cable and strut

stress=force/area

so here i have used this formula ,and i have also resolved the force p=1.8kN in two component i.e pcos$\theta$ and psin$\theta$

and rest of the things i have solved in image given above.