Question

Question 4 (a) Determine the Fourier transform of v(t) in the circuit shown in Figure 4 below. (10 marks) 232 e-21u(t) V (+ + v(t) + IF ele 0.5H 28(1) A Figure 4 (b) For the network shown in Figure 5, by means of the Laplace Transform, evaluate i(t). (15 marks) 2e-fu(t) V + 1F io 1 H HI 112 WW 4u(t) A 122 Figure 5

Answer 1

Given circuit venfonsaltz V(w) { vosi vo5wtzt wa] 8 +23w+1 (4+ gjw) w 'w -26 Cult) + Vlt) 28 (1) mea JOSH Redraw the circuit in the form 4 a) oo fossier tranfoleas frequency doman in fourier transform. fletult)= H2&H)) = 2 2+ jw vow) (w) ( sort2-wa) = arvio iw (4 +2jw) ún (a+ujw) V(W) (10.5+2-w) (4+ 25w) / (برها+و ببن vw) - (4+20w) (-w+&+0:53) 2+jw • josw 2 Answer By using nodal Analysis VW)- ztów uw) Vw) + 되어 + 3 jw jos =2 2 V(W) + 'swiv(w)) + V (W) 2 2(2+uw) jor v(w) (w) { / 2 + 1 out ow] z 2+ 2(27) CS Scanned with CamScanner

2 Given circuit 2 etult) too th IF la & ult la Redraw the circuit in the form of laplace form. Llety = 2 2 sti L (4 ut)) = us 2 13 4 13 s V, m Vizes) V (S) i) la als CS Scanned with CamScanner

By using loop analysis (mesh] loop - 7,15) + 3 (ics)- 13(s)) + s (1/(s) – 1,(s)) +12() = 0 (-1 + $) 115) + (+1) iz(s) + +5)*_(s) = 0 ;;(9) + = 12 13) © loop 2 (s) + 1,5) ( iz(s)-izls)) + Ś C 1s)-1,Cs] 3 Sti 3 Ś 115) 1,18) – sie(s) + (2 +3+$) is(5)=0 St1 2 ts=0 ( -S4 1,(s) + (5+) (119)+*)-(+1+34) is (s=0 (Style 143) + (sti) ii(s) + (8+19 Est, + 5+1) 715) * (vt ) iz(s) = -40% - (14 she) is -4C 5+1) CS Scanned with CamScanner

in 3 5 til)=8(1,6+9)+ ( a +91) 369 = 0 les et ini is(5)=0 -Šils) - S1,(s) -4+ astiti s(s+1) (-s),(3) (s+102 iz (5)=4 s(5+1) th=) .15) + (571) ;;(9)=4 Gap) iz() = (4 + ".) 1, (s)] is19) = (4 * long) 1,09) (ر) © in .418+) S (1 +5)*4 + -418+) (1)-(3) -10. (':*)):19 (**) (2+1) Cs+1) = (1+5)(1-3); (5) is) 45 $+) S -4(st), (1+5%) 4 + S S +1 St5+) a415+15² +45 (145) ($71) ( 5+4 7+5) 1163) 815+) ($+1) (s +$) ls) = -45-45-4 +45? 45-45-45-4 ỉi (5) - s(+1)(1+5) CS Scanned with CamScanner

2 و دیار 0 هاد - ا - و با کی (و + (1)s ندا =ا مرا +گ ها +ر + بدلا من s + و ملایم و 1 - کد8 + (ر) را s²+5+5+8² CS Scanned with CamScanner

6 i,(s) in Equation ③ S ig(9) = [५+ 4-3 (५१-५२-५३-५ S ( (+1) (S+) S+) 13(5) ५ + + (1-5) (45-45-45-५) s (+1) (S+1) CS Scanned with CamScanner

(7 kol at node (= سلام ( (ر) = (ی) + (که (ر) را (22 - (ر) us 4 ربا - ر سے کمه) - ) سال 94) (41ی )s پا کی 8 ای با می) ( +؟ + s4s + s2 (1+) (s) ( ی) - - پایه (-1) - (sel)( )244 ) 45 - (941) (یه پایه) = (و) (1+ی) (۱) )s - وہ 85 84 راهی ها (۱+یا (8+ ) - و - us - کد8 + s 11 کو یه های اداره + و - ( S4 و دو )، و ہاکی - به رسانه ای با = (ہ-وه ای بکر ) ( - ) - باد و دید و با دو ۔ : + 4 tus CS Scanned with CamScanner

% ا- کہا - کد8 ہلارہا کلمه به کی با لایه ها+ y S'+ 8. + - وا -هد8 - s 12 + یہ (1+ يز + + کی ای) = (ر) ها و 3+45-85-8 & و 8 + 26s لایا گیا = (ر)و (1+s ) ( S + دی ای د) Tanswer CS Scanned with CamScanner

Sorry.time isn't adjusted.

,if you have any doubts comment.

I will help you.