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why does it appear the maximum and minimum are solved the exact same way? whats the difference?
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Substituting y = kx into Equation (6) gives: -2(kx* – b) = 1 Substituting this expression for into Equation (5) gives x* -atk
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(0) fra.y= -cn-a) ² - cy-b) ² y = kx grx,y) = kny 4x261) 4x = -26*-a) fan = -2 ax y een ty : -304.6) Tag = -2 fuy trydy) as sco fex, y) = (x ) + (9-18 4- 2n gin, y) = 2nry - 2 (x- ) fy - rly - Yo) fax 2 fy - 2 , kay = 0 we have critical points as socheck the sign of "d" for each critical point

It gives the details about critical point , it is maxima / minima or saddle point

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