Question

A student needs to dilute a 0.28 M Pb(NO3), solution to make 111.0 mL of 0.11 M Pb(NO3)2. Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.28 M Pb(NO3)2 solution that is needed. 0.28 M 0.28 M x 0.11M) 0.11 M 4+ 2.7 x10-4 mL mL 111.0 mL Answer Bank 111.0 mL 111.0 ml 0.11 M 0.11 M 0.28 M 0.28 M 0.11 mL 0.28 mL 111.0 L

I am wondering if this is right? Thanks

Answer 1

The answer is, 43.60 ml of 0.28 M Pb(NO3)2 is needed.

We can use the formula V1N1=V2N2

It is given that N1 = 0.28 M

V2 = 111 mL

N2 =0.11 M

Hence V1 = V2N2 / N1

V1 = (111 mL × 0.11 M) / 0.28 M

= 43.60 mL