Question

(AINA) Suppose in the Euclidean plane two equilateral triangles ABC and ADE (with possibly different side lengths) share a single vertex "A" but do not otherwise overlap and have separate interiors (see below example). What can you conclude about the distances BD and CE? Justify (i.e. prove) your result.

Need help thanks!

Answer 1

So we get and = > BD^2 = a^2 + b^2 - 2ab cos (60 + theta) = CE^2 = > BD = CE rightarrow answer.