Question

You have a summer intern position with a company that designs and builds nanomachines. An engineer with the company is designing a microscopic oscillator to help keep time, and you've been assigned to help him analyze the design. He wants to place a negative charge at the center of a very small, positively charged metal loop. His claim is that the negative charge will undergo simple harmonic motion at a frequency determined by the amount of charge on the loop.

Evaluate the oscillation frequency for an electron at the center of a2.7-μm-diameter ring charged to 1.8×10⁻¹³ C .

Answer 1

According to due Question we know that f = 1/2 pi squareroot q Q/4 pi elementof_0 m R^3 = 1/2pi squareroot (9 times 10^9) times(1.602 times 10^-19) times (1.8 times 10^-13) /(9.11 times 10^-31) times (1.35 times 10^-6) ^3 f = 1.71344 times 10^12 HZ