Question

Find the expected result of the two list comprehension by hand (show your work): list_1 list_2 [10-thing for thing in range (20,1,-1)] [val**3 for val in [1,1,2,2,3,3,4,4] if val!=2] [4]

Answer 1

This problem is related to python programming language.

1.

list_1= [10-thing for thing in range(20,1,-1)]

Above is an example of list comprehension, range(20,1,-1) will generate a sequence from 20 to 1(excluding) in reverse order like 20, 19, 18, 17,......, 2. then each number will be subtracted from value 10 hence the elements in the list_1 will be

10-20, 10-19, 10-18, 10-17, 10-16,....., 10-2 which means -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8.

list_2=[val**3 for val in [1, 1, 2, 2, 3, 3, 4, 4] if val!=2]

In this list comprehension, list_2 will have cubes of each element except for the value 2. hence, the elements for the list_2 will be 1**3, 1**3, 3**3, 3**3, 4**3, 4**3 i.e. 1, 1, 27, 27, 64, 64.

2. Please refer the screenshot for the indentation.

Program implementation:
#function to calculate the required list
def neighbour_sum(lst):
#result list
result=[]
#loop iterates through each element of the list
for i in range(len(lst)):
#if element is first element of the list
if(i==0):
result.append(lst[i]+lst[i+1])
#if element is last element of the list
elif(i==len(lst)-1):
result.append(lst[i]+lst[i-1])
#if element is neither first nor last element
else:
result.append(lst[i]+lst[i-1]+lst[i+1])
#returns the result list
return result
  
#function call to the neighbour_sum() with required input
print(neighbour_sum([1,3,5,6,9]))

  Program implementation and code output screenshot:

Spython main.py [4, 9, 14, 20, 15] 1 2 #function to calculate the required list 3- def neighbour_sum(1st): 4 #result list 5 result=[] 6 #loop iterates through each element of the list 7 for i in range(len(lst)): 8 #if element is first element of the list 9 if(i==0): 10 result.append(1st[i]+1st[i+1]) 11 #if element is last element of the list 12 elif(i==len(1st)-1): 13 result.append(ist[i]+1st[i-1]) 14 #if element is neither first nor last element else: 16 result.append(1st[i]+lst[i-1]+lst[i+1]) 17 #returns the result list 18 return result 19 20 #function call to the neighbour_sum() with required input 21 print(neighbour_sum((1,3,5,6,9])) 15 22

Feel free to ask if you have any doubts in the comment section.

HOPE YOU LIKE THE SOLUTION!!!!

Spython main.py [4, 9, 14, 20, 15] 1 2 #function to calculate the required list 3- def neighbour_sum(1st): 4 #result list 5 result=[] 6 #loop iterates through each element of the list 7 for i in range(len(lst)): 8 #if element is first element of the list 9 if(i==0): 10 result.append(1st[i]+1st[i+1]) 11 #if element is last element of the list 12 elif(i==len(1st)-1): 13 result.append(ist[i]+1st[i-1]) 14 #if element is neither first nor last element else: 16 result.append(1st[i]+lst[i-1]+lst[i+1]) 17 #returns the result list 18 return result 19 20 #function call to the neighbour_sum() with required input 21 print(neighbour_sum((1,3,5,6,9])) 15 22