Question

Page 3 of 16 Prelab-Q1 Let RL = 500 Ω and assume that Vac+/-is 12 VRMS. Determine the size of C1 such that the ripple voltage is no larger than 250 mV peak-to-peak. Assume the frequency of the AC source is 60 Hz. You may use the space below for the analysis, but put your answer in the Prelab TA Verification box (Page 6). Vac+ Vo D1 C1 RL Vac

Answer 1

Summary - it is basic problem so I have shown step by step solution .

(V_r)_p-p = V_dc /2f_0 C_1 R_L V_ac = V_m /squareroot 2 V_ac = 12 v V_dc = (squareroot 2 V_ac) 2/pi = 2V_m /pi V_dc = 2 times squareroot 2 times 12/pi = 10.80 Watt (V_r)_p-p < 250 times 10^-3 10.80/2 times 60 times C_1 times 500 < 250 times 10^-3 C_1 greaterthan 10.80/2 times 60 times 250 times 10^-3 times 500 C_1 greaterthan 7.2 times 10$-4 F C_1 min = 7.2 times 10^-4 F