What is the empirical formula for a compound which contains 0.0134 g of iron, 0.00769 g of sulfur and 0.0115 g or oxygen?
Fe mass = 0.0134 g
Fe molar mass = 55.84g
Fe moles = mass / molar mass = 0.0134 / 55.84 = 2.4 x 10^-4
S moles = 0.00769 / 32 = 2.4 x 10^-4
O moles = 0.0115 / 16 = 7.2 x 10^-4
mole ration of Fe , S ,and O
Fe : S : O = 2.4 x 10^-4 : 2.4 x 10^-4 : 7.2 x 10^-4
= 1 : 1: 3
so
Empirical formula = FeSO3
What is the empirical formula for a compound which contains 0.0134 g of iron, 0.00769 g...
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