1)
We would be using the below formula: -
z=x-
/
/
n
z=17.1-17.9/2.3/
11
z=-1.153
z=x-
/
z=18.1-17.9/2.3/
11
z=0.2884
Looking at the z table, we get the values as 0.1251 for -1.153 and 0.6141 for 0.2884. Hence, 0.6141-0.1251=0.489 is the final answer
1- 2- In a particular lake, all fish weights have a mean of μ = 17.9...
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A large lake is stocked with 30% catfish. You go out on the lake
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