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A toroid with 3.0*10^5 turns per meter has 0.60m inner and 1.0m outer diameter and is...

A toroid with 3.0*10^5 turns per meter has 0.60m inner and 1.0m outer diameter and is powered with 15A of electric current.

What is the magnetic field on a 0.80m diameter circle at the central plane of this toroid?

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Answer #1

B = (mu) (n) (I)

the turn density  n = number of turns = 3 x 10^5 per m

If the current in the solenoid I = 15 A

then the magnetic field at the center of the solenoid is B = 5.67 Tesla

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