Question

How much Oil (in bbl), Water (in bbl) and Hematite (in sacks) are required to make exactly 1000 bbl of 16 ppg oil mud with an oil/water ration of 90/10. Assume an oil density of 6.8 ppg and a Hematite density of 42 ppg.

Answer 1

Volume of oil =V₁

Volume of water=V₂

Volume of Hematite =V₃

Density

w₁=6.8 ppg

water density in ppg=8.33 ppg

so

w₂=8.33 ppg

w₃=42 ppg

So for adding theses three component we find new oil mud.

So mass =density*volume

So v₁w₁+v₂w₂+v₃w₃=v_fw_f

The oil and water ratio is 90/10.So that they can be considered as one volume v that is 90% of oil and 10% water.

v₁=0.9v

v₂=0.1v

v₁+v₂+v₃=1000

v+v₃=1000

So

v₃=1000-v

So put all values in v₁w₁+v₂w₂+v₃w₃=v_fw_f.

0.9*v*6.8+0.1*v*8.33+(1000-v)*42=1000*16

35.047v=26000

v=741.86 bbl

so oil =0.9*v=667.67 bbl

water=0.1*v=74.186 bbl

hematite=1000-v=258.14 bbl