Question

Prob #4: The Mohr circle associated with x-y state of stress on a component is shown below (not necessarily to scale). 5.0 28p D(si) 20 Tiksi) 61 ksi Component Yield Stress in magnitude on planes whose The component is subjected to shear stress of ~ normal is along x or y directions A)2.8 B)56C)6.1 D) 8 E)10 F)12.2 ks G)18.3 G)3.7 14. H)20 l)24.4 )26.2 - 15. Based on the Max. Principal Stress Theory, the factor of safety for yielding is 16. The maximum shear stress within the xy-plane of the component is ~ 17. The normal stress acting on a plane oriented 90 degrees from the maximum principal B) 1.8 C) 2.5 D) 2.2 E) 1.5 F) 2.8 H) 3.0 0.9 D3.1 A) 1.2 ksi. A) 28 B)5.6 C)8.4 D) 7.6 E)4.8 F 1.9 G)9.4 H)3.2 6.5 12.2 stress plane of the component isksi A)2.8 B)5.6 ?)61 D) 8 E)10 F)12.2 G) 183 H)20 I)24.4 )26.2 ksi The component is subjected to absolute maximum shear stress of~ A)2.8 B)5.6 C)61 D) 8 E)10 F)12.2 G) 18.3 H)20 18. 1) 24.4 D262 19. The normal stress acting on the component reaches its largest magnitude along a plane degrees CCW from the x-direction. whose normal is oriented A)29 B)38 C)45 D) 61 E)58 F31 G)52 H)68 14 76 20. The component is subjected to normal stress of~ ksi along the y-direction. A) 28 B)5.6 C)6.1 D)8 E) 10 F) 12.2 G)18.3 H)20 )24.4 )26.2 21. The component is subjected to normal stress of~ ksi on max. shear planes. A) 28 B)5.6 C)6.1 D8 E)10 F)12.2 G)15.0 H)20 1)24.4 )26.2

Answer 1

(D) 8 ksi shear stress along the plane times X &Y tau_xy = 8 ksi (c) 2.5 maximum principle stress T_1 = OB = 15.1 R = 15 + squareroot 89 = 24.4 ksi Factor of safety FS = sigma_y/sigma_1 = 61/24.4 = 2.5 (G) 9.4 maximum shear stress with in the x-y plane, tai_max = R radius of mohr circle tau_max = 9.4 ksi (B) 5.6 ksi on a plane oriented go from the maximum principal stress plane, minimum principle stress will act & sigma_2 = 15 - R = 15 squareroot 89 = 5.6 ksi (F) 12.2 ksi absolute maximum shear stress in this case tau_max -0 sigma_1/2 = 24.4/2 = 12.2 ksi (a) 290 ccw from mohr circle tan 20_p = 8/5 theta_p = 28.9 degree (E) 10 Normal stress along the y-axis sigma_y = 15 - 5 10 ksi (g) 15 ksi