
How to solve to get answer 0.71125?
P(at least one of the test will be positive)
=1-P(none of the test is postive)
=1-(P(have disease and tested negative by both tests)+P(not have disease and tested negative by both tests))
=1-(0.25*0.45*0.4+0.75*(1-0.5)*(1-0.35))=0.71125
How to solve to get answer 0.71125? Questions 12 and 13 refer to the following setup....
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Consider the following domain: . a % of men at age fifty who participate in the routine screen have prostate cancer. .b% of men with prostate cancer will get positive prostate-specific antigen test. • % of men without prostate cancer will also get positive prostate-specific antigen test. 1. Please describe the domain knowledge in terms of probabilities in which C is used to denote prostate cancer and P is used to denote positive prostate-specific antigen test. 2. Please follow Bayesian...
Hello I would like to ask for some help on this two-part
practice question that I have, mainly with the second part as I
don't really get it.
Consider the following domain:
a% of men at age fifty who participate in the routine screen
have prostate cancer.
b% of men with prostate cancer will get a positive
prostate-specific antigen test.
c% of men without prostate cancer will also get positive
prostate-specific antigen test.
Please describe the domain knowledge in terms...
validity of a test
HELP
answer ALL you can !!
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pls answer all
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