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Questions 12 and 13 refer to the following setup. Consider two screening tests for prostate cancer, the Digital Rectal Exam (

How to solve to get answer 0.71125?

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Answer #1

P(at least one of the test will be positive)

=1-P(none of the test is postive)

=1-(P(have disease and tested negative by both tests)+P(not have disease and tested negative by both tests))

=1-(0.25*0.45*0.4+0.75*(1-0.5)*(1-0.35))=0.71125

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