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Image for 5) The voltage across the 3-F capacitor in the figure above IS A) 8 V B)4V C)6V D) 12V E)15V
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Answer #1

here first we solve the total capacitance of the circuit

the capacitance in series

1/Cs = 1 / C1 + 1 / C2

1/Cs = 1 / 3 + 1/ 6

1/Cs = 3/6

Cs = 2 uF

then the charge across the series capacitors are

Q = Cs * V

Q = 2 * 12 = 24C

then the volatege across the 3uF capacitor is

V = Q/C

V = 24 / 3

V = 8v

so the potental across the 3uF capacitor is 8v

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