Question

A thin rectangular plate of uniform areal density σ = 2.98 kg/m£ has length of 43.0 cm and width of 26.0 cm. The lower left hand corner is ochin rectengo arg fund th lengh is ang ti/m-ahs length of 43.0 em and width of 26.0 em. The lower left hand corner la 3 0 There is a circular hole of radius 5.50 cm with center at (x,y) = (15.50, 11.00) cm in the plate. Calculate the mass of plate. 3.05x101 kg You are correct. อ Previous Tries Your receipt no. is 152-1754 Calculate the x-coordinate of CM of the plate. 0.128 m Pretend that the circle is in the plate, but that it has negative mass. Submit Answer Incorrect. Tries 3/10Previous Tries Calculate the distance of the plate's CM from the origin.

Answer 1

(a) Mass of plate = M = Area times density Area = [a times b] - pi(5.50 times 10^-2)62 (43 times 26) times 10^-4 - (pi times 5.50) times 10^-4 Area = 0.110073 m^2 M = 0.110073 times 2.98 M = 0.328 kg \r\n (b) x_cm = 0.328 times 21.5 + delta M-H 15.50/0.328 - M_H and M_H = pi times (5.50 times 10^-2)62 times 2.98 M-H = 0.02830 x = 7.052 + 0.43865/0.2997 x_cm = 24.9938 cm