Question

A wire 35 cm long is parallel to a 0.53-T uniform magnetic field. The current through the wire is 4.5 A. What force acts on the wire?

Answer 1

If the wire is parallel to the field, no cutting is taking place, so no force is produced.

Answer 2

The force action on the wire is zero because the field is parellel to it therefore Lorenz equation gives zero (vector)

Answer 3

The force on a current carrying wire is

F = ILBsin(theta)

I = 4.5 A
L = 0.35 m
B = 0.53 T
theta = 90, so that part cancels out as the sine90 = 1

F=4.5*0.35*0.53sin90

F=0.834N