Question

Problem 1 The following geometry is to be manufactured using a 3D printer that uses spot mode with a spot diameter of 0.03 in. The thickness of each layer is 0.004 in. The print speed is rather slow at 2 in/s and it takes 5 seconds to reposition the print head to its original location. If the machine takes 15 minutes to set up, calculate total cycle time for this print. All dimensions are in inches
its for manufacturing process class

Answer 1

Area of bottom Surface of block A, - 6* 3 - r o's) 17:21 in Area of top surface , 6x 8 - nx lois) - 2x3 This block can be considered as a block combination af 2 blocks, a cubical block with circular convity ( bottom half of block) of a cubical block with circular free Jalar cavity with Area A2 = 11.01 in Diameter of spol = 0.03 inch.. thickness of layer & o.oou inch, Velocity = 2 in/see. rate of volume deposition 0.03x0.064 x 2 rate of Area time required of block = 0.0342 deposition to made 0.06 in2/sec. = A a layer of first block = A, = 17.21 0:06 = 286.83 sec time required to make I layer of and block = t = 2 2 2 = 186.82 0.06

Nos of layer of frost block t block n = thickness of ft thickness of lawyer 0.5 = 105 layers m, 0.004 Nos. of layers in and block no a thickness of 2nd layer thickness of layer 125 layers. ₂ = os 0.004 time setup time - 15min = 900 sec required to change one loyer to other = 5 sec. Total cycle time = (T) = 900 + (n + 2) +5 + m, xt, t xtz = 900 + 250x5 + 125x286.83 + 125x 186.83 = 61357.5 = 17.043 sec. hrs.