Question

For this question, assume baseball pitchers are throwing baseballs (each 146g) at hanging targets. The diagram shows the ball approaching a hanging target from the left side. Assume the baseball hits the target with a horizontal speed of 38 m/s. The target is soft and the ball temporarily sticks to it and moves with the target as it swings up and to the right (as shown by the dashed line). The target has a mass of 2.4 kg. The wire supporting the target is of negligible mass, and rotates without friction about point A. The distance from A to the middle of the target, where the ball hits, is 1.2 m. How far will the target rise vertically, once it is hit by the baseball? wire - - - - - - - 101 ball target

Answer 1

M Collision m w PX, 8 = x, f Px, i = momee → Px, i = 0146838 + "xo om, i den ~ 5.548 kg-m/s xf = (m+M) v = (-196+2.4) = 2.5460 kg-m/s Conservation of momentum xe = x, f 5.548 = 20 546 V - un 2.179 m/s vis vem = v centre of mass Now, work engy theorem gain in PE = loss in KE * (mirigh = 1 (megren = = Vem = (2.12982 ~ 0.242 2x9.8 = 2402 m cm. te