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(3) Given the demand function for a consumer for some meat as follows: 9. = 5 +.02 Y-5 P. +.25 P2 Where q, is the amount of t

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Answer #1

Given, Q1= 5 + 0.02Y - 0.5P1 + 0.25P2

Y = $ 100/ week, P2 = $ 12 / kg

Q1= 5 + 0.02×100 - 0.5P1 + 0.25×12

Q1 = 5 + 2 - 0.5P1 + 3

Q1 = 10 - 0.5P1 (Demand function)

P1 = 20 - 2Q1 (Inverse demand function)

B. Refer the attached picture for the demand curve

P / $ 20 Demand Curve

C. When P1 = $ 20

Q1 = 10 - 0.5×20 = 0

Differentiating the demand function wrt P1, we get

dQ1/dP1 = -0.5

Elasticity of demand = (dQ1/dP1)×(P1/Q1) = -0.5 ×(20/0) = - Infinity

Since quantity demanded at that price is zero.

D. Q1= 5 + 0.02Y - 0.5P1 + 0.25P2

Differentiating the above equation wrt P2 we get

(dQ1/dP2) = + 0.25

Therefore the cross elasticity of demand for meat and fish will be positive. Hence, meat and fish are Substitute to each other.

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