Question

What is the mass (in grams) of a femur (leg bone) having a volume of 118 cc? The density of bone is 1.8 g/cc.

Iron has a density of 7.8 g/cc. What is the mass, in grams, of a 4.4 cm³ piece?

What is the volume (in cc) of a sample of mercury that has a mass of 20.5 g. The density of mercury is 13.6 g/cc.

Aspirin has a density of 1.40 g/cc. What is the volume in cubic centimeters of a tablet weighing 250. Mg? Report your answer using the correct number of significant figures.

What would be the volume, in mL, of a sample of water weighing 550 mg? Report your answer to the correct number of significant figures.

If a piece of gold foil 4 cm x 5 cm has a mass of 1.5 g, and a density of 19.3 g/cc, what is its width or thickness, in cm? Report your answer using the correct significant figures.

Answer 1

Solution a Given Data in Volume of femur= 118cc Density of bone = 18 glee Mass of femur benea? Notas Density - Maske Mays Density x volume Mass of fennur bone = 1.8 g/cc x 118 cc ha D .212.89. So, mass of femur bane=212.49. ? b) Given Data Density of Iron = 7.8 g/cc Volume of im 4. &cm3 = 4.866 3. Mass of irona? Mass - Density x volume D=ņ Mass of inm= 7.8 g/cc x 4.8cc 1. = 3.4.32 g Mass of iron 234.32 q. Scanned with CamScanner

Given Data mass of mercury = 20.5g. Density of mercury = 13.6gec Volume of mercury ? Density = moss Volume volume Mass Density. volume of mercury 20.59 od 13.6g/ec = 1.50CC volume of merceiry in sample= 1.500 . Given Data Density of aspirin 140 glee. weight of Aspirin = 250 mg = 250 mg 1000 q 0.25g. volume of Ang pirine ? Density= mass Densing Volume 0.258 . Volume of Aspirin = to 1.4oglec .: 0:199 cc cs ca volume of Aspirin -0.179 CC

e) Given Data Mass of water = 550mg. = 550 99 0 : 5509 looo Density of water = 1.00 g/m2 Density of water = mass of water volume of water Voleime of Waters 0.5508 1:00g/mL = 0-550 mL volume of waters 0:550 ml. Given Data mass of gold foil = 1.5g utuh Density of gold foil = 1939/CC: Area of Gold foil= 4cm x 5cm = 20 cm width or thickness= ? manity a mass 1 7 Density volume 1.sg cs svolume of gold foixz 19.39|em? CamScanner

UM volume of gold foila 0.078 cm3 volume a Areax width or thicking or height 0.078cm3 = 20cm2 x width width= 0.78 cm3 20 cm² = 0.00 39 cm width=. 3.9x103 cm. So, width of gold foila: 3.9x10-cm C Scanned with CamScanner