Question

50.00 mLof 0.1M NaOH solution is titrated with 0.05M H2SO4solution. Calculate the volume of the H2SO4 solution that is required to completely neutralize the NaOH solution. Leave your answer in 4 significant fIgures.

Answer 1

Number of moles of NaOH,n= molarity x volume in L

n= 0.1 M * 50.00 mL *10^-3 L/ mL

= 5*10^-3 mol

2 NaOH+ H2SO4 ----> Na2SO4 + H2O

2 moles of NaOH requires 1 mole of H2SO4

5*10^-3 moles of NaOH requires (5*10^-3)/2= 2.5*10^-3 moles of H2SO4

So volume of H2SO4 ,V= number of moles/ molarity

V= (2.5*10^-3 mol)/0.05 M

= 0.05 L

= 50.0 mL