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The plane is powered by 4 four-stroke engines running at n=5210rpm. Total effective power of the engines is (table 2). Swept
To [c] P, LP I [kw] 9. 14 15 832 91969, 92 69
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Solution Given - 832KW = 3.2 l = 3.28103 m² (is 4 stroke Engine i N 5210 5210rpm (ii) Total Effective power () Swept volume (832kW Analysis we have BP or total effective power (This is the power at the Engine shaft) |BP = 2INT 60 832 - 2 NXT 60x1oooTherefore, IT IP IT Heat supp IP MF (Kgls) & cv (kJ/kg) 914.3 0.0675X 44000 Am. 30.789). 11 - 914.3 2970(1) Indicated power er - Print Vs x H xk 914.30 1oox Pm x 3.21103 5210 2 60 65.80 bar dro. t Indicated Pressure Brake power =Sair 919 69.9267 28+ x (9.44+373) Sair 1.13 kg/m² now air fuel ratio ma 0:3) = 3.11 MF 0.0675 air consumption / min mair (kg/thank you.

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