Question

The relationship between AG and T (temperature) is linear. Draw the AGº versus T graph of a reaction with the properties described below. You need only label the point at which AGº -0. • The reaction is exothermic • Ang O(Ang = moles of gas products - moles of gas reactants) • At 300 K, the system is at equilibrium and K = 1 (You may upload a photo of the solution (look for the "embed image" icon in the second row of functions above the text box, click on the Canvas tab, then "My Files" to upload). You may also email me the solution.) HTML Editor

Answer 1

Page AG = a + RT end d- Reachon Quotient - Taking Equation im AG account AG - Rend T Similar to y = C - mx limearly decreasing Curive with Slope - Rend OG = C = intercept - m = - Reno 300k Bokt " 46"-o at 300K as KET at 300k Q = K = Equillibrum constant = 1 - end) = lnk=0 at Equillibrium OG=0 OG = -RT INK at Book , K=1 AG = - RX300 x ln ! OG=0