Question

Question 22 of 33 > The crew of an enemy spacecraft attempts to escape from your spacecraft by moving away from you at 0.263 of the speed of light. But all is not lost! You launch a space torpedo toward the foe at 0.341 of the speed of light with respect to you. At what speed in kilometers per second does the enemy crew observe the torpedo approaching its spacecraft? speed: km/s

Answer 1

the Relativistic velouty, lee? = L-V 1-.. here, RO< 3x 109 miser. e = projectie velocity seen by rest observer = 0.341'*C r = observer moving velocity = 0.263*C cz speed of eight a from eah (i)} u = 0.341:0 - 0.263.0 - 6.341.10.263). Tur = 0.08568* c kmi sece or a = 0.08568*C *103 misec = 0.08568x3x10 8 x 103 misec. = 25.705*106x103 mi see. e = 25.7050 106kmisec]