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A proton of mass m undergoes a head-on elastic collision with a stationary nucleus of mass...

A proton of mass m undergoes a head-on elastic collision with a stationary nucleus of mass 3m. The speed of the proton is 730 m/s. Find the velocity of the center of mass of the system.

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Answer #1

Vcm = m1v1 + m2 v2 / (m1 + m2 )

since momentum will be conserved so m1v1 + m2v2 will be same before and after collision

= m*730 /(4m)

=182.5 m/s

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