Question

The positive and zero sequence networks of a 3-bus power system are shown below:

The positive and zero sequence networks of a 3-bus power system are shown below:

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Determine the fault current on each phase for each of the following faults: 

  • a) Solid 3-phase fault at bus 3 

  • b) LG fault at bus 3 (on phase A) 

  • c) LL fault at bus 3 (on phases B and C) 

  • d) LLG fault at bus 3 (on phases B and C)

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Answer #1

20 Positive sequence Impedance, at node-3/bus - 3 Zeg at bus- 3 yo.05 10.05 jal 120 2010-1 jo 120 Bolj 3yo.cs 0. 13 0.05 0.05Date Page hey 3 Zero. Sequence Impedance Zoey at a a Zoey 0.05 * 0.05 m) my 10.3 Foor Converting Detta to stor. 0.3x0,3- 0.30@ Solid 3 phare fault at bus. 3 formula for fault Current 120 0.03) E If Zrey 140-33.33% for 30 fault If = Ta by = 2 = te 1LL fault at Bus - 3 - 3 x) 0.03 +0.03 - Zeq + Zrey | 14. - 28.867 box LL fault. If y = - 13 R8.867 +28.867 IB I L = Ic= -IB IJa = I x Zoey Zzeg + Zooq I = 12.025 1 I= 32. = 3x9.2784 27.83 2 = 27.83 T = Ja, t I gotta = 0 IA In + Zotha 14 = Ig the

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