Question

Question 1: Write a python program that finds all numbers divisible by 7 but not multiple of 5. The range of number for searching is between 2000 and 3200 (both included). Output should be printed in a comma-separated sequence on a single line .

Answer 1

X La *cj.py - C:\Users\Basheer\Desktop\cj.py (3.7.4)* - O File Edit Format Run Options Window Help n=[] #take n as empty list for x in range (2000, 3201): #take range from 2000 to 3200 if(x ==0) and (x5!=0): # condition divisible of 7 and not multiple of 5 n.append(str(x)) #append to empty list n print(','.join(n)) #print list

Le Python 3.7.4 Shell - O X File Edit Shell Debug Options Window Help Python 3.7.4 (tags/v3.7.4:e09359112e, Jul 8 2019, 19:29:22) [MSC v.1916 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license()" for more information. >>> == RESTART: C:\Users\Basheer Desktop\cj.py 2002, 2009, 2016, 2023,2037,2044,2051,2058,2072,2079,2086,2093,2107,2114,2121,2128, 2142,2149, 2156,2163,2177, 2184,2191, 2198, 2212,2219, 2226, 2233, 2247, 2254, 2261, 2268, 2282,2289, 2296, 2303,2317, 2324,2331, 2338, 2352,2359, 2366, 2373,2387,2394,2401, 2408, 2422, 2429,2436, 2443,2457,2464, 2471,2478, 2492,2499, 2506, 2513,2527, 2534, 2541, 2548, 2562, 2569,2576, 2583, 2597,2604, 2611,2618,2632, 2639,2646,2653, 2667, 2674, 2681, 2688, 2702, 2709, 2716, 2723,2737.2744.2751.2758.2772, 2779,2786,2793,2807. 2814.2821.2828. 2842, 2849,2856, 2863,2877, 2884, 2891,2898, 2912,2919, 2926,2933, 2947, 2954, 2961,2968, 296,3003, 3017, 3024, 3031,3038, 3052, 3059, 3066, 3073,3087,3094, 3101,3108, 3122,3129, 3136,3143,3157, 3164, 3171, 3178, 3192,3199

CODE:

n=[] #take n as empty list
for x in range(2000,3201): #take range from 2000 to 3200
if(x%7==0) and(x%5!=0): # condition divisible of 7 and not multiple of 5
n.append(str(x)) #append to empty list n
print(','.join(n)) #print separated with single line

Answer 2

num=[]

for i in range(2000,3200):

    if(i%7==0) and (i%5!=0):

        num.append(i)

print(num)