Question

. Determine what is calculated for n = 5:

unsigned int F(unsigned int n)

{

if(n == 0)

return 1;

return n ∗ F(n − 1);

}

Write an iterative version of the function in this problem

Answer 1

Answer :

F(5) = 5 * 4 * 3 * 2 * 1 * 1 = 120

iterative version of the function is

unsigned int F(unsigned int n){
    unsigned int result = 1;
    while(n>0){
        result *= n;
        n--;
    }
    return result;
}