Question

A cell phone's power amplifier produces an RF output of 0.460 between the amplifier and antenna is 1 dB. The antenna has no gain. The cell phone radiates an field Ej the normal The electric field is comprised of y and z field components: Éey + Eez The magnitude of the y component of the field is 40 m V/in while the z component strength is 20 m V/in. Using G calculate the total electric charge on the surface of the metal plate. Example 3.3 of the text is a u reference. (20 pts.) in the direction of a metal plate whose dimensions are 24 inches square (lies in the x-y plane so l vectór points in the x direction). The plate is 6 inches from the cell phone in the x-direction. auss' Law, l de

Answer 1

Given that A cell phone's power amplifier produces on RC output of 0.460 walts antenna is 1 dB. The cell phone radiates an electric field e in the direction of a metal plate whose dimensions are 24 inches square. P_t = 0.46 watts, 460 m watts p_e = p_t 10 = 460 10^-0.1 p_e = 365.39 m walts power loss = -1 dB d = 6 inch = 6 times 2.54 cm = 15.24 cm n = 24 inch^2 24 (2 - 5)^2 cm^2 A = 150 cm^2 E_e_y + E_e_z = 40 j + 20 I m/inch s = p_e/4 pi d^2 \r\n s = 365.39/1000 times 7/4 times 22 times 15.24/100 times 15.24/100 s = 1.252 w/m^2 s = E^2/20 20 = 120 pi R E^2 = 5 times 20 E = squareroot 520 = squareroot 1.252 times 120 times 22/7 c = 21.73 v/m (single direction of plane)