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2.1 The following shows two identical sealed flasks, one containing He and one containing Ne. Both flasks are at the same temd) If the two gases were combined in a third identical flask at the same temperature, the final pressure would be 1.5 atm.

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Answer #1

As pV= nRT

P = pressure

V= volume

n= number of moles

R = Universal gas constant

T = temperature

So the volume and temperature of two flasks are same. And also R is constant itslef.

So pressure is directly proportional to number of moles.

So He is having more pressure than Na so moles of He are more.

And as number of atoms = moles × avagadro number

Hence as He is having more moles .

So atoms of He gas are more than Na

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