Question

Applications of Integration in Thermodynamics 2018-06-16 6 of 6 ? Part A dT where ??-60 10Jmol 1 R-8.31 JK-1 mol 1 T1-298K, and T2-350K. Give your answer to two significant figures T RT2 Submit Request Answer Part B Evaluatev dV where R-8.31 Jk1mor1, n-1.00 mol, T-298K, V, 0.100L, and V2-0.500L. Give you answer to three signifionat figures Value Units

Answer 1

integral^T_2_T_1 increment H /RT^2 dT = increment H /R integral^T_2_T_1 1/T^2 dT = increment H /R [-1/T]^T_2_T_1 = -increment H /R [1/T_2 -1/T_1] = -6010 /8.31 [1/350 -1/298] = -6010 /8.31 [298 -350 /298 times 350] = = 0.360 integral^V_2_V_1 nRT /V dV = nRT [ln V]^V_2_V_1 = nRT [ln V_2 /V_1] = 1(8.31) (298) ln (0.5 /0.1) = 3985.57