Question

1.) Electrons are accelerated through a voltage difference of 285 kV inside a high voltage accelerator tube. What is the final kinetic energy of the electrons?

2.85E5 eV

2.)What is the speed of these electrons in terms of the speed of the light? (Remember that the electrons will be relativistic.)

???

Answer 1

Potential difference V 285000 V Kinetic energy of the electrons is 28500*1.6*104-19 4.56*104-15 where m mass of electron -9.11 x 1031kg m'- relativistic mass m/v[1-(v/c) 2 ] 0.0556-{[ 1 / v[1-(v/c) 2 ]-1) {[ 1 / v[1-(v/c) 2 ] } = 1.0556 v[ 1-(v/c) j = 0.947 [1-(v/c)' ]-0.897 The Speed of electron is v 0.32c