To construct a solenoid, you wrap insulated wire uniformly around a plastic tube 14cm in diameter and 50cm in length. You would like a 2.0❝A current to produce a 2.4❝kG magnetic field inside your solenoid.
apply magnitic fiedl due to solonoid as B = uo n i
where n = N/L
so B = uoNi/L
N = BL/uoi
N = 2400e-4 * 0.5/(4pie-7* 2)
N = 47770.7 turns
length=2pirN
L = 2*pi*0.07*47770.7
L = 21 Km
r=0,07m
h=0,50 m
I=2 A
B=2 400
B=mu0*N*I/h
mu0 --4pi*10powered-7
N -- number of turns on the solenoid
I -- current
h -- height of the solenoid
From here you get how many turns of wire you have
N=B*h/(mu0*I)
The length of the wire is I hope you agree
L=N*2*pi*r
To construct a solenoid, you wrap insulated wire uniformly around a plastic tube 14cm in diameter...
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