Question

Create a function NumEven( std: forward_list-int> SList) that computes and returns the number of even values in a singly linked list SList of type std: forward_list-int> If there is no even value or the list is empty, return 0. Select the appropriate C++ statement for each of the below to implement the function. unsigned NumEven (std:: forward_list<int> Slist) { Select] Select ] Select ] }

All in C++

Answer 1

SOLUTION:

As the function needs to return unsigned number so declare unsigned num = 0;
Now we need to iterate through list and check the number is divisible by 2 using mod increment num for (auto n: SList ){ if (n % 2 == 0) num++; }
Now return num;

Remaining are wrong statements.

I have provided the code and output for a clear view.

The 3 statements to be filled are :

unsigned num = 0;

for (auto n: SList ){ if (n % 2 == 0) num++; }

return num;

CODE ATTACHMENTS:

5 6 7 8 9 10 11 12 13 14 15 16 17 #include<iostream> #include<forward_list> unsigned NumEven(std::forward_list<int> Slist) { unsigned num = 0;//declaring variable. // Loop to iterate through Slist. for (auto n: Slist){ if (n % 2 - 0) num++; } return num;//returning the count. } int main() { 1/declaring list. std:: forward_list<int> SList; SList.assign({1,2,3,4,5,6});//assigning values. //printing the count. std::cout<<"Number of even numbers : "<<NumEven (SList); } Number of even numbers : 3 ... Program finished with exit code 0 Press ENTER to exit console. I

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