1)
P = 314 kPa
= 314*10^3 Pa
= 3.14*10^5 Pa
Area of upper part = pi*(diamter/2)^2
= 3.14*(6.1/2 cm)^2
= 3.14*(3.05 cm)^2
= 29.2 cm^2
= 2.92*10^-3 m^2
Now use:
P = F/A
3.14*10^5 Pa = F / (2.92*10^-3 m^2)
F = 917 N
F = 0.917 KN
Answer: 0.92 KN
2)
Molar mass of CO,
MM = 1*MM(C) + 1*MM(O)
= 1*12.01 + 1*16.0
= 28.01 g/mol
mass(CO)= 19 g
use:
number of mol of CO,
n = mass of CO/molar mass of CO
=(19 g)/(28.01 g/mol)
= 0.6783 mol
Given:
V = 5.0 L
n = 0.6783 mol
T = 30.0 oC
= (30.0+273) K
= 303 K
use:
P * V = n*R*T
P * 5 L = 0.6783 mol* 0.08206 atm.L/mol.K * 303 K
P = 3.3731 atm
Answer: 3.4 atm
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