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A differential amplifier with a constant current source is shown. The circuit parameters are: Vec = Vee = 5 V, R. = 1 ks, R1
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De analysis > +5V skw 5kw deger 01 Iku 9.3k t + [0-65V 0.65V TEL NE LIE2 Nc4 Icz Q Az UBA 0.650 -SV = -4-350 VB4 = Ncq : - 5t2 Noi avela Ver Noz 5- (5k XI (1) a 2.4390 NCE E Vc-VE 2.437 +0.65V E-0.650 NEI = N(E2FNCE = 3.09V Gain (A) = -gm. Rc 3 Gm a

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