Question

solve for x:

1+2sinx=0

Domain[-pi,pi]

Answer 1

Salution - ceis on 1+2 Sinx =0, nefn] Implenes sinx= -1 og Sina=- sinh v Sinn = 1) or Sinx = sin( I) 0 (Because Sint-O) =-Sine) we know that ich sino-sina implies O= nin +(-1)", NEZ Hence from we have sina asin (1) imples Nana &(-1)" (I), NEZ+2 For = 0, we have from N= 0 + (-1) I I [2 ] For s= -1, we chave from 1 Ne nn + (-1) (-1)=– n + I n=-57 € (-7,70 6 For n= –2, we have from 2 – 2n + (-1) 2 (-5) = 27-7 or n = 11 I & [-7,7 For sel, we have from 2 n = to (-1) (-1) = x + 1 = 778E7, 71

For n=2, we have from @ = 27 + (-1)^(-7) = 27-I = 115 & [-7, 7] Hence 1+2 sinx=0, RE[-n, T] 57. The Completres 6 the Salution. tmplies n=