Question

6.

Vector $8f8koFDZA5wAAAABJRU5ErkJggg==$ has a magnitude of 3 at an angle of 35° to the x-axis.

Vector $8X5j197ngCkj0k8uUT3YsAAAAASUVORK5CYII=$ has a magnitude of 1 at an angle of 10° to the x-axis.

Vector $rV28wk2WAe9qBvFcgAAAABJRU5ErkJggg==$ has a magnitude of 10 at an angle of 15° to the y-axis.

Find the x and y components of $8f8koFDZA5wAAAABJRU5ErkJggg==$ , $8X5j197ngCkj0k8uUT3YsAAAAASUVORK5CYII=$ , and $rV28wk2WAe9qBvFcgAAAABJRU5ErkJggg==$ .

14. If $wP3GdDNsYKM4AAAAABJRU5ErkJggg==$ has a magnitude of 9 units and points along the positive y axis and $pvm4Nvtly3xMi06hoAAAAASUVORK5CYII=$ has a magnitude of 7 units and points 25° above the positive x axis, what is the magnitude and direction of the cross product ?

Answer 1

Solh (6) Ã = 3 8 = 1 C = 10 in for u and y component of A. A = A cos 350 = 3 cos 35° Ax = 2.46. A = A sin 35' = 3 sin 35° - 1.72 i & and y component of B. Bx = B costo = 1 cos10° = 0.98 By = B sin 10 = I sin 10° = 0.17 i n and y component of c. Cx- C sin 15° - lo sin 15° = 2-59 C = C Eos 15 = 10 cos15° = 9.66. (147 Given, u = 9 units in the y-asis. ū = 7 units 25° above the n-avis Now. o. 90-25° = 65°. ū x 3 = uv sind - 97 sin65 = 57.10 units. Tux Aduheen ected in Z-asis Iar to both s i and 2