Question

Question 33 of 35 1.0 Points If Prz > k] = .6700, find the value of k O A. 0.44 OB.O O C. 0.67 O D.-0.44 O E.-0.67 Reset Selection Save Previous Next here to search are B0-

Answer 1

This is a normal distribution question with
$\\Mean (\mu)= 0 \\Standard\;Deviation (\sigma)= 1 \\Since\; we\; know\; that \\z_{ score } = \frac{x-\mu}{\sigma}$
p = 0.6700

Given in the question
P(Z < k) = 0.67
This implies that
P(Z < 0.4399131656732339) = 0.67

With the help of formula for z, we can say that
$\\ k = \mu + z\sigma \\\implies x = 0.0 + (0.4399131656732339)1.0$
$k = 0.4399 \approx 0.44$

PS: you have to refer z score table to find the final probabilities.
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