Question

Given that

Tds = d(V f) +

and , is a constant

a) Find and

b) Find . Hint. You have to integrate.

Answer 1

Question

Equation is given

AP + (: A)P = SPL

Now We integrate this equation and putting Value of, f then equation will become the only function of temperature and volume and take partial derivation of this equation with respect to V taking temperature is constant and vice versa.

2 vention given f quordion. Tds = d(vf) -- of du t=cTt a constant llow In tegoeding enqualitioun - Stoss «f) + Sfdu TS: Vf + fu TS = veytt CTANT ST ds=t/as : 3 f in this = TS a Equetion - 3 TSvett +% v S = VCT3 + $735 -- 3 @ Now fatine partial derivative a s with restent CScanned with CamScanner

a = CT3 + < T3 40 73 74 - 3 from Ecuation ① Now qs with respect to T faking partial derivatica v is constant 2.22999999999999999999999999 2 = 3V672 + BOUT? 2 = 464721 - D ②) From Equation ④ value ofs is given by 18= 4cuts - Scanned with CamScanner