Question

3) Review the problem in Exercise 6.22 on page 271 in the book. "(Total Sales) Use a double-subscripted array to solve the following problem.."Solve the problem as much as you can, if you don't have a complete solution you will get partial credit for your effort. Sample output is provided below er the salesperson, product, and total sales. ter -1 for the salesperson to end input. 1 2 3 The total sales for each salesperson are displayed at the end of each row, and the total sales for each product are displayed at the bottom of each col 3 2 00 0.00 .00 0.00 2.00 0.00 0 0.00 0.00 0.00 0.00 o -1.00 0.00 0.00 0.00 -1.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0 0.00 1.00 0.00 o.00 0.00

hi I need help on this C programming problem and I want exact same out also please use functions to break down main and methods.
thank you

Answer 1

If you have any doubts,please give me comment...

#include<stdio.h>

#define MAX_SIZE 5

int main(){

const int max_col=5,max_row=4;

double sales[max_row][max_col];

int i, j;

for(i=0; i<max_row; i++)

for(j=0; j<max_col;j++)

sales[i][j] = 0.0;

int salesperson, product;

double total_sales;

printf("Enter the salesperson, product, and total sales.\n");

printf("Enter -1 for the salesperson to end input.\n");

scanf("%d", &salesperson);

while(salesperson!=-1){

scanf("%d %lf", &product, &total_sales);

sales[salesperson][product] = total_sales;

scanf("%d", &salesperson);

}

double total[max_col];

for(i=0; i<max_col; i++)

total[i] = 0.0;

printf("\nThe total sales for each salesperson are displayed at the end of each row, and the total sales for each product are displayed at the bottom of each column.\n");

printf("\n%-4c", ' ');

for(i=0; i<max_col; i++)

printf("%4d\t",i);

printf("\n");

for(i=0; i<max_row; i++){

printf("%-4d", i);

double tot=0.0;

for(j=0; j<max_col; j++){

printf("%.2lf\t", sales[i][j]);

tot+=sales[i][j];

total[j]+=sales[i][j];

}

printf("%.2f\n", tot);

}

printf("%-4c", ' ');

for(i=0; i<max_col; i++)

printf("%.2lf\t", total[i]);

printf("\n");

return 0;

}