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Air at 108 kPa and 20 oC is compressed steadily by a 5.3 kW compressor to...

  1. Air at 108 kPa and 20 oC is compressed steadily by a 5.3 kW compressor to 620 kPa and 170 oC . The mass flow rate of air is 1.55 kg/min. The surrounding temperature or the ambient temperature is 17 oC. Calculate the loss of available energy or exergy destroyed in kW.

Assume Cp of air as 1.005 kJ/kg K and gas constant R as 0.287 kJ/kg K . Remember to change temperatures to the Kelvin scale. (Hint: Here entropy transfer due to mass is negative. T2 is less than T_isentropic. So you know how to solve this problem as there is q_out.)

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Answer #1

P= lod klat Ti= 20°C Data hivan: ń = 1.55 Kg/min = 0.026833 19/dee. 7293% To = 17°C = 290k Solution P22 620 kPa The change iNegative value of answer means there is loss in available energy

Second law efficiency = (4.5392÷5.3) = 0.8564 => 85.64 %

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