The answer above is almost correct, except for the fact
that SO3^2- is NOT trigonal planar. It will be tetragonal due to
the extra lone pair on Sulfur.
It is hard to draw in a text editor by I 'll try to explain
the structures.
a: SO3^2-:
Sulfur in the center. It attaches to 1 oxygen atom through
a double bond. This one oxygen atom will have 2 lone pairs. The
sulfur also attaches to the other 2 oxygen atoms through a single
bond. These 2 oxygen atoms each have 3 lone pairs. Each of these 2
oxygen atoms has a formal negative charge. Finally there is a lone
pair on the sulfur.
b SO4^2+:
Sulfur in the middle again. It attaches to 2 oxygen atoms
through double bonds. Each of these oxygen atoms have 2 lone pairs
each. The sulfur also attaches to 2 more oxygen atoms through
single bonds. Each of these 2 oxygen atoms have 3 lone pairs each.
These last 2 oxygen atoms have a formal negative
charge.
c NO2^-:
Nitrogen in the middle, attached to 1 oxygen atom through a
double bond. This oxygen atom has 2 lone pairs. Attached to the
other oxygen atom through a single bond. This oxygen atom has 3
lone pairs and a formal negative charge. Finally there is a lone
pair on the nitrogen.
d: CO3^2-:
This is identical to a: SO3^2-, except replace the sulfur
with carbon. The final lone pair (on sulfur) will be
missing:
Carbon in the center. It attaches to 1 oxygen atom through
a double bond. This one oxygen atom will have 2 lone pairs. The
carbon also attaches to the other 2 oxygen atoms through a single
bond. These 2 oxygen atoms each have 3 lone pairs. Each of these 2
oxygen atoms has a formal negative charge.
Thanks so much for the explanation. I really understood why the CO3^2- has an ideal structure. Two electrons are added, one to each oxygen, therefore each of them is left with a formal charge -1. That's always better than adding electrons to carbon, because oxygen is more electronegative.
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