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19-Fall 2017 PH, chapter 19pdf 4906229 dtcoment ,id-3592 102 12/curset/20178 Pors.211--1/chapter%2019pf MORE PROBLEMS TO WORK ON TOGETHER Find the direction and magnitude of a x b in each case: 1) a = 22 m/s into the board, b 0.23 T into the board 2) a = 22 m/s out of the board, b = 0.23 T to the right 3) a = 22 m/s into the board, b = 0.23 T to the right 4) a = 22 m/s into the board, b = 0.23 T to the left 5) a = 22 m/s out of the board, b = 0.23 T up 6) a = 22 m/s out of the board, b-0.23 T down 20 o e 畚 @i]..I R here to search N ^ㅁ^^よ巳
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Answer #1

We know that

|A×B| = ABsin \theta

So

1).

22×.23×sin0

=0 hence it's a null vector so no meaning of direction here.

2)

22×.23×sin90

=5.06

And direction will be upwards.

3)

22×.23×sin90

=5.06 and direction will be downwards.

4) 22×.23×sin90

5.06 and direction will be upwards.

5)magnitude will be same i.e 5.06 and direction will be to the left.

6) magnitude will be same that is 5.06 and direction will be to the right.

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