Question

Question 8 4 pts An N - 1,070-turn conducting loop with an area of A-0.055 m² rotates in a uniform magnetic field so that the induced emf has a sinusoidal time dependence as shown. What is the strength of the magnetic field, in milli-Tesla, in which the loop rotates? 1.0 milli-Tesla - 10-3 Tesla. Please round your answer to the nearest whole number (integer). 20 V "редадут - 1 (5) 4.0 2007 Equation: Ep = N ABW Solve for B and multiply your answer by 1000 to express B in milli- 2x Tesla. Read Ep and w from the graph. Note that w where is the period of the sinusoidal т oscillation (Hint: period time from peak to peak).

Answer 1

An N - 1,070-turn conducting loop with an area of A-0.055 m² rotates in a uniform magnetic field so that the induced emf has a sinusoidal time dependence as shown. What is the strength of the magnetic field, in milli-Tesla, in which the loop rotates? 1.0 milli-Tesla - 10-3 Tesla. Please round your answer to the nearest whole number (integer). emf 20 V 12 28 44 1 (5) 4.0 20 36 - 20 V + 2007

The induced emf is given by,$\varepsilon =NAB\omega$ .It is given,N=1070 ,A=0.055 m² ,T= 16 s

27 20 IT = T 16
and $20 =1070\times 0.055\times B\times \frac{\pi }{8}$

or, ;

Eight identical capacitors are connected in three different circuits as shown. The ac current source in each circuit is the same. Rank the rms current from the largest to the smallest. B с V sin 21 sin 2 sin 2 Hint: 1 = V/Xc and the capacitive reactance, Xc 1 WC

Answer: $I=\frac{V}{X_{C}}=V\omega C$ ; larger the C ,larger the current;

A sin 2 C С
For this diagram; $C_{A}=\frac{C}{2}$ ;

B sin 2 C C С
For this diagram ;$C_{B}=\frac{C\times 2C}{C+2C}=\frac{2C}{3}$

с sin 24 CE C
For this diagram; $C_{C}=\frac{C\times C\times C}{C+C+C}=\frac{C}{3}$

or,   $C_{B}>C_{A}>C_{C}$

Hence,